Consider the hydrogenation of benzene to form cyclohexane C6H6(l) + 3H2(g)-->C6H12(l)
Delta H for combustion to CO2(g) and/or H20(l) at 298 K for C6H12, C6H12 and H2 is -3270, -4000, and -286 kJ mol-1, respectively. Cp for C6H6, H2, and C6H12 is 100+0.3T, 20+0.05T and 110+0.2 T J K-1mol-1
1) Show that delta H for hydrogenation at 298 K is 128kJ mol-1
2) Deduce delta U for hydrogenation at 298 K
3) Deduce delta H for hydrogenation at 50 K