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Give the possibility of randomly selecting a z-score

Probability based on normal distribution.

1. A z-score of z = +1. A z-score of z = +2.00 indicates a position located exactly two standard deviations above the mean.

True

False

2. for a population with? = 100 and s = 20, the X value corresponding to z = 1.50 is X = 130.

True

False

3. A population with? = 100 and s = 20 is transformed into z-scores. The resulting distribution of z-scores will have a mean of zero.

True

False

4. One advantage of transforming X values into z-scores is that the transformation always creates a normal distribution.

True

False

5. for a population with? = 100 and s = 10, the score corresponding to z = 1.50 is X = ________.

a. X = 101.5

b. X = 105

c. X = 110.5

d. X = 115

6. Random sampling requires that each individual in the population has an equal chance of being selected.

True

False

7. A container has 4 red marbles and 5 blue marbles. If one marble is selected randomly, after that the probability of obtaining a red marble is 4/5 or 0.80.

True

False

8. For a normal distribution, the proportion in the tail beyond z = +1.00 is p = .1587, and the proportion in the tail beyond z = -1.00 is p = -.1587. (Points: 1)

True

False

9. If a vertical line is drawn throughout a normal distribution at z = 1.00, the proportion to the left of the line will be equal to 0.8413.

True

False

10. For a normal distribution, the possibility of randomly selecting a z-score greater than z = -2.00 is p = .0228.

True

False

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## Q : Find the xbar distribution of sample mean

Evaluate your answers for parts (a) and (b). Is the probability in part (b) much higher? Why would you expect this.