Calculate what is the molar mass of the solute
Pure benzene has a normal freezing point of 5.5°C. a solution containing 11.4g of a molecular substance dissolved in 150.0g of benzene (Kf=5.12°C/m) has a freezing point of 1.20°C. what is the molar mass of the solute?
Expected delivery within 24 Hoursrs
A projectile is fired with speed v0 at an angle theta from the horizontal from the horizontal as shown in the figure.Consider your advice to an artillery officer who has the following problem.
Calculate the moles of calcium carbonate present in a 25.00 mL sample of standard, assuming the standard is known to have a hardness of 95.4 ppm (hardness due to CaCO3).
As a chemist for an agricultural products company, you have just developed a new herbicide,"Herbigon," that you think has the potential to kill weeds effectively.
The acid dissociation constant for benzoic acidC6H5CO2H is 6.5x10-5.Determine the equillibrium constant of each species in a 0.050Mbenzoic acid solution.
Calculate the pressure that must be applied to achieve reverse osmosis of 0.504 M NaCl separated by a semipermeable membrane from a solution that is 0.0020 M in NaCl at 22 deg Celsius.
A 65 g ice cube at 0°C is heated until 40 g has become water at 100°C and 25 g has become steam at 100°C. How much energy was added to accomplish the transformation?
Gasoline is composed of hydrocarbons. Which additive, ethanol or MTBE, is more compatible (similar) with gasoline? Why?
A sample of propane (c3h8) is placed in a closed vessel together with an amount of O2 that is 2.50 times the amount needed to completely oxidize the propane to CO2 and h20 at constant temperature.
The second engine receives this energy rejected by the first one, converts some of the work, and rejects the rest to a reservoir at 300 K. If the thermal efficiency of both engines is the same what is the temperature T?
If acetic acid is the only acid that vinegar contains Ka = 1.8 x 10^- 5, calculate the concentration of acetic acid in the vinegar. The pH is 3.15.
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!