We were given mass and volume and we were asked to find limiting reactant, in second question we were asked to find percent by mass of oxygen in CaCO3.
Calculate what the limiting reactant is in the reaction between copper (II) oxide and hydrochloric acid.
CuO(s) +2HCl (aq)->CuCl2(aq)+H2O(l)
Suppose that you react 0.698 g of copper (II) oxide with 0.00400 L of 6.00 M HCl ( 0.00400 of 6.00HCl is equal to 0.0240 moles of HCl) .Calculate the % by mass of oxygen in CaCo3.