Angle between the velocity vector and acceleration vector


A race car moveson a circle of constant radius b. If the speed of the car varies with time t according to the equation v=ct, where c is a positive constant, show that the angle between the velocity vector and the acceleration vector is 45 degrees at time t=sqrt(b/c)

Request for Solution File

Ask an Expert for Answer!!
Physics: Angle between the velocity vector and acceleration vector
Reference No:- TGS0711950

Expected delivery within 24 Hours