In the bird-on-a-wire group work example, how do you expect the angle and tension to be related? Remember that this is static equilibrium, so the acceleration is zero-no angry bird slingshot here! Answer 1-As long as we keep the bird's weight constant and everything is in static equilibrium, the tension and angle are completely independent. 2-If you increase the tension (relative to the bird's weight mg), you expect the wire to sag less, so the angle gets smaller. 3-Birds can never be in static equilibrium. 4-If the angle is big, there must be a lot of tension. Thus, as you increase the tension relative to the bird's weight, the wire must sag more and the angle gets larger. which one is the right answer?