Complete the following:
Q1: The manager of the quality department for a tire manufacturing company wants to know the average tensile strength of rubber used in making a certain brand of radial tire. The population is normally distributed and the population standard deviation is known. She uses a Z test to test the null hypothesis that the mean tensile strength is 800 pounds per square inch. The calculated Z test statistic is a positive value that leads to a p-value of .009 for the test. If the significance level is .01, the null hypothesis would be rejected. TRUE
The level of significance indicates the probability of rejecting a false null hypothesis. FALSE
Q2: When conducting a hypothesis test about a single mean, other relevant factors held constant, increasing the level of significance from .05 to .10 will decrease the probability of a Type II error. TRUE
Q3: Given the following information about a hypothesis test of the difference between two means based on independent random samples, what is the standard deviation of the difference between the two means? Assume that the samples are obtained from normally distributed populations having equal variances.
H0: A ≤ B, and H1: A > B X ¯ 1 = 12, X ¯ 2 = 9, s1= 5, s2 = 3, n1 =15, n2 =14.
A. 2.039
B. 1.546 xxxxx
C. 1.792
D. 4.159
E. 2.389
Q4: Which if any of the following statements about the chi-square test of independence is false?
A. If ri is row total for row i and cj is the column total for column j, then the estimated expected cell frequency corresponding to row i and column j equals (ri) (cj)/n
B. The test is valid if all of the estimated cell frequencies are at least five
C. The alternative hypothesis states that the two classifications are statistically independent
D. The chi-square statistic is based on (r-1)(c-1) degrees of freedom where r and c denote, respectively the number of rows and columns n the contingency table