What will be the volume of HCl 0.2750M, measured by burette, needed to consume all of the Calcium Carbonate that is contained in a block of that material that has dimensions of 2.5 x 1.0 x 0.5 inches?
given: 1 inch = 2.54 cm
D= m/v
CaCO3 = 100.09 g/mol
CaCO3(s) + 2HCL (aq) -> CaCl2(aq) + H2O(l) + CO2(g)