Suppose that ammonia decomposes at 600 Kelvin to establish equilibrium NH3<--> 1/2N2(g)+3/2H2 for which K=0.395. You have a box volume of 1.00 liter into which you inject 2.65 grams of NH3 at 600K. What will be the final concentrations of NH3,N2, and H2 after equilibrium is established. I know the answers are suppose to be H2=.170M, NH3=.0424M, N2=.0568M, but I don't know how to get them.