A mixture of oxygen and hydrogen is analyzed by passing it over hot copper oxide and through a drying tube. Hydrogen reduces the cu0 according to the reaction
Cuo (s) + h2 (g) ----> Cu (s) + H20 (l), and oxygen re oxidizes the copper formed according to Cu (s) + 1/2 o2 (g) -----> Cu0 (s).
At 25 degrees Celsius and 750. Torr, 125 cm^3 of the mixture yields 82.5 cm^3 of dry oxygen measured at 25 degrees Celsius and 750. Torr after passage over Cu0 and the drying agent. What is the original composition of the mixture?