#1 For which reactions
I) O2(g)+H2(g)→H2O2(l)
II) C(s, diamond) + O2(g) → CO2(g)
III) N2(l) + 3 F2(g) → 2 NF3(l)
IV) C(s, graphite) + 3/2 O2(g) + H2(g) →
? CO2(g) + H2O(g)
V) 2 Fe(s) + 3/2 O2(g) → Fe2O3(s)
would ?Hr? = ?Hf??
#2Use these three reactions
CH4(g) + 2 O2(g) -→ CO2(g) + 2 H2O(g)
?H? = -802 kJ
CH4(g) + CO2(g) -→ 2 CO(g) + 2 H2(g)
?H? = 247 kJ
CH4(g) + H2O(g) -→ CO(g) + 3 H2(g)
?H? = 206 kJ
to determine the appropriate enthalpy of change of
CH4(g)+3/2 O2(g)-→CO(g)+2H2O(g).
#3 Remember to calculate to the correct number of sig figs.
Given the following thermodynamic data,
2H2O(g) → O2(g) + 2H2(g)
?Hrxn = 483.6kJ
H2O(g) → H2O(l) ?Hrxn = -44.0kJ
What is the molar heat of formation for liquid water, H2O (l)?
Answer in units of kJ/mole.