What is the minimum volume in ml of 596 m hcl needed to


Problem- One way to make chlorine is to let manganese dioxide react with hydrochloric acid according to the equation:
4HCl + MnO2? Cl2+ MnCl2 + 2H20 .

What is the minimum volume (in mL) of 5.96 M HCl needed to prepare 513.0 mL of dry chlorine when the gas is obtained at 28.6 degrees celcius and 763 torr?

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Chemistry: What is the minimum volume in ml of 596 m hcl needed to
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