We are given the mass of the unknown Trial 1: 0.1100g Trial 2: 0.1200g volume of NaOH used Trial 1: 10.34 mL Trial 2: 11.28 mL moles of NaOH used: we have to calculate this for both trials as well as molar mass of acid if monoprotic also for both trials and then the last question we need to find the average of the molar mass.