Now, instead of an equation of a circle, we are given an equation of an ellipse (x^2) / (a^2) + (y^2) / (b^2) = 1 a > b > 0
a. We can obtain an ellipsoid by revolving the ellipse around the x-axis. What is the surface area of this ellipsoid? By the way, there is a common convention to let c = sqrt(b^2 - a^2) along the way to make the derivation a bit less messy.
b. Based on what you get in part a, what if we have a ≈ b, or c ≈ 0?