Transshipment problem as a linear-programming model


Problems:

Question:

DSS Inc. is an electronics company with production facilities located in Atlanta, Boston, and Chicago. Components produced at these facilities may be shipped to the firm's regional warehouses that are located in Edison and Fargo. From the warehouses the firm supplies retail outlets located in Houston, Indianapolis, and Jacksonville.

The capacity of each production facility is presented below:

Atlanta

Boston

Chicago

800

500

700

The firm must meet the demands specified below for each retail outlet:

Houston

Indianapolis

Jacksonville

900

600

500

The transportation cost per unit from each facility to each warehouse is specified below:

 

Atlanta

Boston

Chicago

Edison

6

1

3

Fargo

4

8

1

The transportation cost per unit from each warehouse to each retail outlet is specified below:

 

Houston

Indianapolis

Jacksonville

Edison

8

3

4

Fargo

2

3

8

The firm has to determine an optimal transshipment plan that minimizes total transportation cost while meeting the demands in each retail outlet and not exceeding the capacity at each production facility.

(a) Formulate the transshipment problem as a Linear-programming model and determine the optimal transshipment plan.

(b) In the analysis so far we have ignored the cost of operating each warehouse. If a warehouse is operated, a fixed cost must be incurred. If a warehouse is not operated, the fixed cost can be avoided but no shipment can occur through that warehouse. ). The fixed costs for warehouse operation are given below:

 

Cost

Edison

$10,000

Fargo

$5,000

 

 

Determine the optimal plan that minimizes the total cost (total cost is defined as the sum of the cost of transportation and the cost warehouse operation).

My partial Answer:

680_Diagram.jpg

XAE , XAF , XBE  , XBF , XCE , XCF , XEH , XFH , XEI , XFI , XEJ , XFJ

Capacity Constrains:

XAE + XAF ≤ 800

XBE + XBF ≤ 500

XCE + XCF ≤ 700

Demand Constrains:

XEH + XFH ≤ 900

XEI + XFI ≤ 600

XEJ + XFJ ≤ 500

XAE + XBE + XCE = XEH + XEI + XEJ

XAF + XBF + XCF = XFH + XFI + XFJ

Objective Function:

Minimize the cost = 6XAE + 4XAF + XBE + 8XBF + 3XCE + XCF + 8XEH + 2XFH + 3XEI + 3XFI + 4XEJ + 8XFJ

b) Three options:

Keep both warehouses open: add operating cost of $15000

Close Fargo: add operating cost of $10000

Close Edison: add operating cost of $5000

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Mathematics: Transshipment problem as a linear-programming model
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