The natural time period of this system is found to be 05 s


A helical spring of stiffness k is cut into two halves and a mass m is connected to the two halves as shown in Fig. 2.81(

a). The natural time period of this system is found to be 0.5 s. If an identical spring is cut so that one part is one-fourth and the other part three-fourths of the original length, and the mass m is connected to the two parts as shown in Fig. 2.81

(b), what would be the natural period of the system?

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Mechanical Engineering: The natural time period of this system is found to be 05 s
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