Te hydrogenation of ethylene is c2h4g h2g-----gt c2h6g


The hydrogenation of ethylene is: C2H4(g) + H2(g)-----> C2H6(g). Calculate the change in enthalpy of Hydrogenation from 298 K to 398 K. The Cp values are C2H4: 43.6 J/K mol and C2H6: 52.7 J/K mol

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Chemistry: Te hydrogenation of ethylene is c2h4g h2g-----gt c2h6g
Reference No:- TGS0607246

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