Question- For the reaction 3Ru2 + (aq) + 2Nb(s)?3Ru(s)+2Nb3+(s) which has Eorxn=1.554V. The half cells are constructed with the following quantities- A 10. g Ru electrode immersed in 250. mL of 1.00 M Ru(NO3)3, and a 9.3 g Nb electrode immersed in 250. mL of 1.00 M Nb(NO3)2. What is the Erxn in volts when these two cells are connected at 298 K?
Hello Experts please provide me the detailed computation for above question