The gas-phase decomposition of n2o5 is the first-order


The gas-phase decomposition of N2O5 is the first-order process with a rate constant of 1.50 x 10^-3s^-1 at 55*C. The decomposition is:

N2O59g0 ---> 2NO2(g) + 1/2 O2(g)

If 5.0 g of N2O5 are placed in vessel 1 and 10.0 g of N2O5 in vessel 2 and the vessels are at the same temperature (55*C) and the same pressure, how much time is required for half of the N2O5 to decompose in each vessel?

A. Vessel 1 requires twice as much time as vessel 2
B. Vessel 2 requires twice as much time as vessel 1
C. Vessel 1 requires four times as much time as vessel 2
D. Vessel 1 requires three times as much time as vessel 2
E. Vessel 1 requires the same amount of time as vessel 2

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Chemistry: The gas-phase decomposition of n2o5 is the first-order
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