The exact amount of 50-m naoh needed to neutralize the


A 9.11-g piece of zinc metal is dissolved in 75-mL of 3.5-M HCl and hydrogen gas is evolved. The exact amount of 5.0-M NaOH needed to neutralize the remaining H+ ions and to precipitate out the Zn2+ ions as Zn(OH)2 is then needed. Determine the mass of Zn(OH)2 precipitate formed

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Chemistry: The exact amount of 50-m naoh needed to neutralize the
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