The equilibrium constant for the following reaction is


The equilibrium constant for the following reaction is 6.59×10-2 at 927 °C.

2 SO3(g) <-----> 2 SO2(g) + O2(g)    K = 6.59×10-2 at 927 °C

Calculate the equilibrium constant for the following reactions at 927 °C

(a)   2 SO2(g) + O2(g) <----> 2 SO3(g)    K = ________

(b)   SO3(g) <-------> SO2(g) + 1/2 O2(g)   K = _________

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Chemistry: The equilibrium constant for the following reaction is
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