The antibiotic paromomycin p forms a complex with a


The antibiotic paromomycin (P) forms a complex with a particular 27-nucleotide RNA construct (R).  Dissociation of this complex can be described  schematically (in aqueous solution) as:

 

             RP <----> R + P                    Kd= .520                     at 25ºC

where the equilibrium constant KD is commonly referred to as the dissociation constant.  Assuming one begins with 0.0780M of RP complex (only):

Determine the equilibrium amounts of [RP] and [P] at 25 ºC.  ???

Suppose that the value of KD changes to 1.47* when the temperature is raised to 37 ºC.  Does the equilibrium of part (a) shift to the right (R); shift to the left (L); or remained unchanged (U).

Is this process (reaction) exothermic or endothermic or is DH = zero at equilibrium (put correct answer/word in the blank)?

Starting from the final equilibrium amounts determined in part (a) at 25 ºC, determine the equilibrium amounts of [RP] and [P] if the temperature is raised to 37 ºC.

Hints: quadratics should use the positive roots and keep three significant digits.  If pressed for time, set up rxn table/quadratics for partial credit. 

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Chemistry: The antibiotic paromomycin p forms a complex with a
Reference No:- TGS01141160

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