The analysis of ca2and mg2in urine samples could be

Question

The analysis of Ca²⁺and Mg²⁺in urine samples could be performed in a way similar to the EDTA analysis of the calcium content in water. For example, a 25.0 mL aliquot of a urine sample (buffered to pH = 10.0) required 17.2 mL of 0.0776 M EDTA to react with all of the Ca²⁺and Mg²⁺ions in the sample. Then another identical 25.0 mL urine sample was analyzed, except this one was treated with NaOH to precipitate all of the Mg²⁺from the solution. This second solution required 13.2 mL of the 0.0776 M EDTA to react with the Ca²⁺ions. Report the moles of Ca²⁺and Mg²⁺in the urine