Te freezing point of a solution of 0494 g of k3fecn6 mw


Problem- A- Explain why the boiling points of HF, NH3, and H2O are all much higher than those of their third row analogues (HCl, PH3, H2S).

B- Explain why solid water floats in its liquid whereas solid HF and NH3 do not exhibit this behavior.

C- The freezing point of a solution of 0.494 g of K3Fe(CN)6 (MW = 329) in 100 g of water is -0.093°C. Calculate the effective number of ions formed per mole of solute that dissolves given Kf(H2O) = 1.86 K kg mol-1.

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Chemistry: Te freezing point of a solution of 0494 g of k3fecn6 mw
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