Stone launched vertically upward


Assignment:

Question 1. Luigi launches a stone vertically upward from the top of a cliff. The height of the stone above the base of the cliff is appoximated by the model h=65+10t-5t^2 , where t is time in second and h is height in metres

a) How high is the stone above the base of the cliff after 3 seconds?

h = 65 + 10t - 5t^2
h = 65 +10(3) - 5(3)^2
h = 65 +30 - 45
h = 50 m

b) How long does it take for the stone to reach 50m above the base of the cliff?

h = 65 + 10t - 5t^2
h = 65 + 10t - 5t^2
-65 + 50 = 10t - 5t^2
-15 = 10t - 5t^2
can someone help me from here?

c) How long does it take for the stone to hit the ground at the base of the cliff?

Solution Preview :

Prepared by a verified Expert
Physics: Stone launched vertically upward
Reference No:- TGS01885971

Now Priced at $30 (50% Discount)

Recommended (99%)

Rated (4.3/5)