Physics question regarding torque.
A 3.0 m bar with negligible mass is fastened such that it hangs straight out from the side of a building. A cable which can provide a maximum force of 256.0 N is attached to the end of the bar on one end, with the other end attached to the building wall above the bar. The angle between the cable and the metal bar is 23.0 degrees (marked as theta in the image). How far from the building wall can a 11.4 kg mass be hung from the metal bar such that the cable does not snap? Express your answer in m. Hint: You will have to determine the two torques on the bar such that the system is in equilibrium. Set your pivot as the point where the bar is connected to the building. You should have one positive and one negative torque acting against one another.