Rionbspyield secondary hydrogenyield of primary hydrogen


Organic Chemistry:

For PROPANE (CH3CH2CH3)      

RATIO: yield secondary Hydrogen/yield of primary hydrogen = 2/6 *4.5 = 1.5   therefore secondary:primary ration = 1.5:1

60% Secondary product & 40% primary product 

My question is - The percentages above (60% & 40%) how do we calculate these???

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Chemistry: Rionbspyield secondary hydrogenyield of primary hydrogen
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