The collar C is moving downward with an acceleration of 1 m/s2. At the instant illustrated shown, it has a speed of 2 m/s that gives links CB and AB an angular velocity ωAB = ωCB = 10 rad/s. Find out the angular accelerations of CB and AB at this instant.
Hints:
a) You are asked to determine aAB and aCB
b) aB = aC + aB/C)t + aB/C)n
c) aB/C)t = raCB
d) aB/C)n = rωCB2
