Question- The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 5.15-g sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCl(aq) and passed over a reducing agent so that all the antimony is in the form Sb3^+ (aq). The Sb3^+ (aq) is completely oxidized by 20.2 mL of a 0.145 M aqueous solution of KBrO3(aq). The unbalanced equation for the reaction is
BrO3^- + Sb^3+ yields Br^-+ Sb^5+
Calculate the amount of antimony in the sample and its percentage in the ore.
1. ? in g
2. ? in %
Anyone can tell me how to solve it step by step so that I will be able to understand what is going on?