Question- how would you prepare 130 x 102 ml of a 0936m


Question- How would you prepare 1.30 x 10^2 mL of a 0.936M NaOH solution, starting with a 6.54M stock solution?

a) Volume of stock solution needed-? mL

b) Volume of water needed-? mL

I have read my textbook moreover I still don't understand so please provide me a very condensed, simple to know answer?

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Chemistry: Question- how would you prepare 130 x 102 ml of a 0936m
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