Question- Consider a voltaic cell based on Fe/Fe^2+ half-cell and a Cu/Cu2+ half-cell. If [Cu^2+] = 0.30 M, what must be [Fe^2+] to be increase Ecell by 0.15 V above E0cell at 25C?
E0red= -0.44 V (Fe^2+ + 2e- --> Fe)
E0red= +0.34V (Cu^2+ +2e- --> Cu)
How do you know which one is reduction and which one is oxidation?
Ecell = E0cell - RT/nF x ln Q (we're using this equation to solve this problem right?)
This is the question for that you have to provide expert solution