q in a differentiating circuit r10 kwand c22mufif

Question

Q. In a differentiating circuit, R=10 kW,and C=2.2μF.If the input voltage goes from 0V to 10 V at a constant rate in 0.4s, determine the output voltage.

Solution:

e₀ = RC x d/dt(e_i)
     =  RC x de_i/dt

R = 10 kW, C = 2.2μF

de_i/dt = (10-0)/0.4 = 25 V/s
e₀ = (10 x10³) x (2.2 x 10^-6 ) x 25 = 0.55 V