Assignment:
The purification of copper by electrolysis involves an anode of impure copper and a cathode of pure copper. During the electrolysis, copper (II) ions leave the anode slab and plate onto the cathode slab.
The reaction at the anode is Cu(s) = Cu2+(aq) +2e-
The reaction at the cathode is Cu2+(aq) + 2e- = Cu(s)
Therefore, it would appear that these two reactions cancel out leaving an emf of zero.
- How to calculate the amount of energy required to purify copper being that the emf is zero.
- How much energy (in joules) is required to purify a given amount (i.e. 100g) of copper?
- Is heat produced? Why or why not? If so, how much (heat)?
Your answer must be typed, double-spaced, Times New Roman font (size 12), one-inch margins on all sides, APA format.