Pulse jamming and soft-decision decoding


Solve the following problem:

In coded and interleaved DS binary PSK modulation with pulse jamming and soft-decision decoding, the cutoff rate is

R0 = 1 - log2( 1 + ae-αεc/N0)

1346_DS binary PSK modulation with pulse jamming.jpg


where α is the fraction of the time the system is being jammed, Ec = εbR, R is the bit rate, and N0 ≡ J0.

a. Show that the SNR per bit, εb/N0, can be expressed as

εb/N0 = 1/αR  In  α/21-R0 - 1

b. Determine the value of α that maximizes the required εb/N0 (worst-case pulse jamming) and the resulting maximum value of εb/N0.

c. Plot the graph of 10 log(εb/r N0) versus R0, where r = R0/R, for worst-case pulse jamming and for AWGN (α = 1). What conclusions do you reach regarding the effect of worst-case pulse jamming?

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Other Engineering: Pulse jamming and soft-decision decoding
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