Proving that equivalence relation modulo forms a ring


Assignment:

Prove that the equivalence relation modulo m where m is an integer, forms a ring.

Also, does this same equivalence relation form a field and why?

For this proof, you are given that [a]m (m is a subscript) represents an equivalence class modulo m, where m is an integer. We also know that for any two integers, a and b, that

[a]m + [b]m = [a + b]m and
[a]m[b]m = [ab]m

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Algebra: Proving that equivalence relation modulo forms a ring
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