Problem-symplectic matrix and eigenvalues and multiplicity


Question:

Symplectic Matrix, Eigenvalues and Multiplicity

A 2n x 2n M is symplectic if MTJM = J where J is the (also 2n x 2n) matrix ( 0   -I ).
                                                                                                                  ( I    0 )

Prove that if λ is an eigenvalue of M , then so is λ-1 , and that these have the same multiplicity.

Show furthermore that if λ and µ are eigenvalues of M, and λ ≠ µ ,then the corresponding eigenvectors gλ, gµ have the property that

gT µJ gλ = 0

Solution Preview :

Prepared by a verified Expert
Algebra: Problem-symplectic matrix and eigenvalues and multiplicity
Reference No:- TGS01933377

Now Priced at $20 (50% Discount)

Recommended (95%)

Rated (4.7/5)