Problem on electrochemical analysis


An unknown sample of N2+ gave a current of 2.36µA in an electrochemical analysis. When 0.500 mL of solution containing 0.0287M N2+ was added to 25.0 mL of unknown, the current increased to 3.79 µA.

a. Denoting the initial, unknown concentration as [Ni2+]i, write an expression for the final concentration of , [Ni2+]f after 25.0 mL of unknown was mixed with 0.500 mL of standard. Use dilution factor for this calculation.

b. In a similar manner write the final concentration of added standard Ni2+, designated as [S]f.

c. Find the [Ni2+]i in the unknown.

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Chemistry: Problem on electrochemical analysis
Reference No:- TGS0506822

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