Problem based on complexometric and precipitation titration


Assignment Problem: Analytical Chemistry

Complexometric and Precipitation Titration

Directions: Answer the questions on a short white bond paper. For problem solving, write the systematic solution and box the final answer.

Problem 1: Define the following:

a. Ligand

b. Chelate

c. Tetradentate chelating agent

d. Adsorption indicator

e. Argentometric titration

f. EDTA displacement titration

g. Water hardness

Problem 2: Why are multidentate ligands preferable to unidentate ligands for complexometric titrations?

Problem 3: Describe three general methods for performing EDTA titrations. What are the advantages of each.

Problem 4: Why does the charge on the surface of precipitate particles change sign at the equivalence point of a titration?

Problem 5: A solution was prepared by dissolving about 3.0 g of NaH2Y2·2H2O in approximately 1 L of water and standardizing against 50.00-mL aliquots of 0.004423 M Mg2+. An average titration of 30.27 mL was required. Calculate the molar concentration of the EDTA.

Problem 6: A solution contains 1.569 mg of CoSO4(155.0 g/mol) per milliliter. Calculate

a. The volume of 0.007840 M EDTA needed to titrate a 25.00-mL aliquot of this solution.

b. The volume of 0.009275 M Zn2+ needed to titrate the excess reagent after addition of 50.00 mL of 0.007840 M EDTA to a 25.00-mL aliquot of this solution.

c. The volume of 0.007840 M EDTA needed to titrate the Zn2+ displaced by Co2+ following addition of an unmeasured excess of ZnY2- to a 25.00-mL aliquot of the CoSO4 solution. The reaction is

CO2+ + ZnY2-à CoY2- + Zn2+

Problem 7: Calculate the volume of 0.0500 M EDTA needed to titrate

a. 29.13 mL of 0.0598 M Mg(NO3)2.

b. The Ca in 0.1598 g of CaCO3.

c. The Ca in a 0.4861-g mineral specimen that is 81.4% brushite, CaHPO4·2H2O (172.09g/mol).

d. The Mg in a 0.1795-g sample of the mineral hydromagnesite, 3MgCO3Mg(OH)2·3H2O (365.3 g/mol).

e. The Ca and Mg in a 0.1612-g sample that is 92.5% dolomite, CaCO3.MgCO3(184.4 g/mol).

Problem 8: Calculate the pCrO4 in a solution formed by mixing 50.0 mL 0.50 M K2CrO4 with 50 mL 0.50 M AgNO3.(Ksp = 1.1x10-12)

Problem 9: Calculate the pCrO4 in a solution formed by mixing 50.0 mL 0.50 M K2CrO4 with 125 Ml 0.50 M AgNO3.(Ksp = 1.1x10-12)

Problem 10: Calculate the pAgin a solution formed by mixing 20.0 mL 0.50 M Na3PO4,20 mL 1.20 M AgNO3 and 20 mL H2O. (Ksp = 1.3 x 10-20)

Problem 11: A 0.970 g sample containing KCN and inert materials was dissolved in water for Liebig titration. Concentrated NH3 and NaI were added to the solution for enhanced end point detection. The solution required 40.1 mL 0.101 M AgNO3 to reach the turbid end-point. Find the %KCN in the sample.

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Chemistry: Problem based on complexometric and precipitation titration
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