Problem- Your current SOP for making a caustic solution for removing tartrates in your tanks calls for using 100 grams of NaOH in 10 Liters of water. You want to try using KOH to reduce the sodium in your wastewater.
Part a) How many moles of NaOH are in 100 grams expressed in 1 decimal use 40 grams for the molecular weight of NaOH?
Part b) What is the molar concentration of your NaOH solution according to the SOP expressed in 2 decimals?
Part c) How many grams of KOH per 10 liters of water would you need to weigh to get the same molar concentration (use 56 grams for the molecular weight of KOH) expressed with no decimal?
If possible just a brief explanation how you got the answer?