Problem- A chemical reaction between lead (II) nitrate and sodium chromate produces lead (II) chromate and sodium nitrate.. The reaction is expected to produce 88.6 grams of PbCrO4. If the percent yield is 72.8% how many moles of lead (II) nitrate reacted?
Reaction: Pb(NO3)2(aq) + Na2CrO4(aq) ---> PbCrO4(s) + 2NaNO3 (aq)
{Molar masses: 331.21 g/mol Pb(NO3)2, 161.98 g/mol Na2CrO4, 323.19 g/mol PbCrO4, 85.00 g/molNaNO3}
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