Print the chemical equation for the activity of aluminum metal and silver(I) ion from the amalgam. Which reactant is the reducing agent? _________________ b. (7 points) Calculate the Kc for the spontaneous reaction between metallic silver (I) ion and solid aluminum metal. How spontaneous is this process based on two thermodynamic ideas? What should you do with the number if your ancient calculator cannot handle the overflow? c. (7 points) Calculate the cell voltage and determine if the cell is spontaneous when the estimate initial concentrations are 0.0060 mM silver(I) ion and 0.00001 mM aluminum ion. d. Bonus (4 points): Using the table of reductions values explain why silver ion is the reactant and why silver metal is a sacrificial anode that protects mercury from oxidizing into mercury(I) or mercury(II) ion.