A tank containing mw = 45 kg of liquid water initially at T1 = 318 K has one inlet and one exit with equal mass flow rates. Liquid water enters at T1 = 318 K and a mass flow rate of 270 kg/hr. A cooling oil immersed in the water removes energy via heat transfer at a rate of 7.6 kW (see schematic below). The water is well mixed by a paddle wheel so that the water temperature, T(t) is uniform throughout the tank. The power output to the water from the paddle wheel is 0.6 kW. The pressures at the inlet and exit are equal; therefore, the difference in specific enthalpy between the inlet (T1) and exit [T(t)] is given by: hi - he = c [T1 - T(t)] with c the specific heat of water, c = 4.2 kJ/kg.K All kinetic and potential energy effects can be ignored. Plot the variation of temperature with time. To do so, you will need to solve a first-order, ordinary differential equation, with the boundary condition: T(t=0) = T1 = 318 K.