One way to analyze sulfur is by comustion of the sample, which produces SO2 and SO3 that can be bubbled through H2O2 to produce H2SO4.
The H2SO4 is then titrated against NaOH in the reaction H2SO4 + 2NaOH ? Na2SO4 + 2H2O.
If 8.08 mg of a substance was burned, and the resulting H2SO4 required 6.10 mL of 0.0109 M NaOH to reach the end point, was is the percent mass of sulfur in the sample (three sig. figs)?
S = 32.066 g/mol
O = 15.9994 g/mol
H = 1.00794 g/mol