Number of surjections from nm
Use the inclusion-exclusion principle from the last homework to show that the number of surjections from Nm to Nn is given by
n^m - (n choose 1)((n-1)^m) + ... + ((-1)^n-1)(n chooce n-1)(1^m)
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Use the inclusion-exclusion principle from the last homework to show that the number of surjections from Nm to Nn is given by n^m - (n choose 1)((n-1)^m) + ... + ((-1)^n-1)(n chooce n-1)(1^m)
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