Let x be a normal random variable with mean 30 and standard
Let X be a Normal random variable with mean 30 and standard deviation 8. Find its 90th percentile (i.e. find a number y such that P(X < y) = 0.9)
(provide one digit to the right of decimal point)
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let x be a normal random variable with mean 30 and standard deviation 8 find its 90th percentile ienbspfind a number y
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