Let us assume that Cd(OH)2(s) is completely insoluble, which signifies that the precipitation reaction with NaOH(aq) (presented in the transition) would go to completion.
Cd2(aq)+2NaOH(aq) → Cd(OH)2(s)+2Na(aq)
If you had a 0.650 L solution containing 0.0170 M of Cd2+(aq), and you wished to add enough 1.25 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH-(aq) for the precipitation.