If the rate constant of a first order reaction is 487x10-5


If the rate constant of a first order reaction is 4.87X10-5 s-1 at 15 degrees C compute the rate constant at 80 degrees C if the activation energy is 250 Kj/mole (R=8.314J/K)

Describe how to got it and each part of the formula

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Chemistry: If the rate constant of a first order reaction is 487x10-5
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