If the rate constant of a first order reaction is 487x10-5
If the rate constant of a first order reaction is 4.87X10-5 s-1 at 15 degrees C compute the rate constant at 80 degrees C if the activation energy is 250 Kj/mole (R=8.314J/K)
Describe how to got it and each part of the formula
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if the rate constant of a first order reaction is 487x10-5 s-1 at 15 degrees c compute the rate constant at 80 degrees
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