If the ionization energy for rubidium is 403 kjmol the


If the ionization energy for rubidium is 403 kJ/mol . The electron affinity for iodine is -295 kJ/mol. Utilize these values and Hess's law to compute the enthalpy for the following reaction

Rb(g) + I(g) ---> Rb+(g) + I-(g)
ΔH=?

Request for Solution File

Ask an Expert for Answer!!
Chemistry: If the ionization energy for rubidium is 403 kjmol the
Reference No:- TGS0910980

Expected delivery within 24 Hours