If a 0 b 0 show that fx a1- e-bx is everywhere


Question: 1. If a > 0, b > 0, show that f(x) = a(1- e-bx) is everywhere increasing and everywhere concave down.

2. Let g(x) = x - kex, where k is any constant. For what value(s) of k does the function g have a critical point?

3. A function of the form y = a(1 - e-bx) with a, b > 0 and a horizontal asymptote of y = 5.

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Mathematics: If a 0 b 0 show that fx a1- e-bx is everywhere
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