If 5 g of sodium metal reacts completely with excess


The combination reaction of sodium metal and chlorine had to form sodium chloride is represented by this equation:

2Na+Cl2--> 2NaCl

If 5 g of sodium metal reacts completely with excess chlorine gas, an 11.5 g of Nacl is actually obtained what is the precent yield. I know that the actual yield. How do i find the theoretical yield so I can put it in the percent yield equation.

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Chemistry: If 5 g of sodium metal reacts completely with excess
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